To cite this work or the weyl
package in publications
please use Hankin (2022). In a very nice
youtube
video, Richard Borcherds discusses the fact that first-order
differential operators do not commute, but their commutator is itself
first-order; he says that they “almost” commute. Here I demonstrate
Borcherds’s observations in the context of the weyl
package. Symbolically, if
$$ D=\sum f_i\left(x_1,\dots,x_n\right)\frac{\partial}{\partial x_i}\qquad E=\sum g_i\left(x_1,\dots,x_n\right)\frac{\partial}{\partial x_i} $$
where fi = fi(x1, …, xn) and gi = gi(x1, …, xn) are functions, then
$$ DE=\sum_{i,j}f_i\frac{\partial}{\partial x_i}\,g_i\frac{\partial}{\partial x_j} =\sum_{i,j}f_ig_j\frac{\partial}{\partial x_i}\frac{\partial}{\partial x_j} + f_i\frac{\partial g_j}{\partial x_i}\,\frac{\partial}{\partial x_j} $$
$$ ED=\sum_{i,j}g_i\frac{\partial}{\partial x_i}\,f_i\frac{\partial}{\partial x_j} =\sum_{i,j}g_if_j\frac{\partial}{\partial x_j}\frac{\partial}{\partial x_i} + g_i\frac{\partial f_i}{\partial x_j}\,\frac{\partial}{\partial x_j} $$
so E and E “nearly” commute, in the sense that ED − DE is first order:
$$DE-ED= \sum_{i,j}f_i\frac{\partial g_j}{\partial x_i}\,\frac{\partial}{\partial x_j}-g_i\frac{\partial f_i}{\partial x_j}\,\frac{\partial}{\partial x_j} $$
Above we have used the fact that partial derivatives commute, which
leads to the cancellation of the second-order terms. We can verify this
using the weyl
package:
D <- weyl(spray(cbind(matrix(sample(8),4,2),kronecker(diag(2),c(1,1))),1:4))
E <- weyl(spray(cbind(matrix(sample(8),4,2),kronecker(diag(2),c(1,1))),1:4))
F <- weyl(spray(cbind(matrix(sample(8),4,2),kronecker(diag(2),c(1,1))),1:4))
D
## A member of the Weyl algebra:
## x y dx dy val
## 7 8 0 1 = 4
## 4 3 0 1 = 3
## 1 5 1 0 = 2
## 6 2 1 0 = 1
(E and F are similar). Symbolically we would have
$$D= \left( x^6y^2 + 2xy^5\right)\frac{\partial}{\partial x}+ \left(4x^7y^8 + 3x^4y^3\right)\frac{\partial}{\partial y}. $$
The package allows us to compose E and D, although the result is quite complicated:
## A spray object. Summary of coefficients:
##
## a disord object with hash ab0b4d525d3ef5030fcdc229e07f50175ee9dc3f
##
## Min. 1st Qu. Median Mean 3rd Qu. Max.
## 1.0 4.0 8.5 20.5 22.0 128.0
##
##
## Representative selection of index and coefficients:
##
## x y dx dy val
## 11 3 1 0 = 6
## 9 12 1 1 = 16
## 9 4 0 1 = 12
## 8 6 2 0 = 2
## 10 4 1 1 = 3
## 12 3 2 0 = 1
However, the Lie bracket, ED − DE,
(.[E,D]
in package idiom) is indeed first order:
## A member of the Weyl algebra:
## x y dx dy val
## 8 12 0 1 = -8
## 4 9 1 0 = 30
## 15 14 0 1 = 16
## 12 9 0 1 = -20
## 5 7 0 1 = 24
## 7 6 1 0 = 8
## 13 8 1 0 = -4
## 14 8 1 0 = 8
## 8 7 0 1 = -9
## 13 9 0 1 = -32
## 10 3 1 0 = -3
## 9 11 1 0 = 8
## 7 7 0 1 = -18
## 2 9 1 0 = -4
## 3 10 0 1 = -18
## 9 6 1 0 = 6
## 6 6 1 0 = -34
## 9 4 0 1 = 12
## 10 12 0 1 = 36
Above, looking at the dx
and dy
columns, we
see that each row is either 1 0
or 0 1
,
corresponding to either ∂/∂x
or ∂/∂y respectively. Arguably
this is easier to see with the other print method:
## A member of the Weyl algebra:
## -8*x^8*y^12*dy +30*x^4*y^9*dx +16*x^15*y^14*dy -20*x^12*y^9*dy
## +24*x^5*y^7*dy +8*x^7*y^6*dx -4*x^13*y^8*dx +8*x^14*y^8*dx
## -9*x^8*y^7*dy -32*x^13*y^9*dy -3*x^10*y^3*dx +8*x^9*y^11*dx
## -18*x^7*y^7*dy -4*x^2*y^9*dx -18*x^3*y^10*dy +6*x^9*y^6*dx
## -34*x^6*y^6*dx +12*x^9*y^4*dy +36*x^10*y^12*dy
We may verify Jacobi’s identity:
## A member of the Weyl algebra:
## empty sparse array with 4 columns
Borcherds goes on to consider the special case where the fi and gi are constant. In this case the operators commute (by repeated application of Schwarz’s theorem) and so their Lie bracket is identically zero. We can create constant operators easily:
## A member of the Weyl algebra:
## x y z dx dy dz val
## 0 0 0 0 0 1 = 3
## 0 0 0 1 0 0 = 2
## 0 0 0 0 1 0 = 1
## A member of the Weyl algebra:
## x y z dx dy dz val
## 0 0 0 0 0 1 = 7
## 0 0 0 1 0 0 = 6
## 0 0 0 0 1 0 = 5
(above, see how the first three columns of the index matrix are zero, corresponding to constant coefficients of the differential operator; symbolically $D=2\frac{\partial}{\partial x}+\frac{\partial}{\partial y}+3\frac{\partial}{\partial z}$ and $E=6\frac{\partial}{\partial x}+5\frac{\partial}{\partial y}+7\frac{\partial}{\partial z}$. And indeed, their Lie bracket vanishes:
## [1] 0