--- title: "Objects `dx`, `dy`, and `dz` in the `stokes` package" author: "Robin K. S. Hankin" output: html_vignette bibliography: stokes.bib vignette: > %\VignetteEngine{knitr::rmarkdown} %\VignetteIndexEntry{dx} %\usepackage[utf8]{inputenc} --- ```{r setup, include=FALSE} set.seed(0) library("stokes") knitr::opts_chunk$set(echo = TRUE) options(rmarkdown.html_vignette.check_title = FALSE) ``` ```{r out.width='20%', out.extra='style="float:right; padding:10px"',echo=FALSE} knitr::include_graphics(system.file("help/figures/stokes.png", package = "stokes")) ``` ```{r label=definedxdydz} dx <- d(1) dy <- d(2) dz <- d(3) ``` To cite the `stokes` package in publications, please use @hankin2022_stokes. Convenience objects `dx`, `dy`, and `dz`, corresponding to elementary differential forms, are discussed here (basis vectors $e_1$, $e_2$, $e_2$ are discussed in `ex.Rmd`). @spivak1965, in a memorable passage, states:

Fields and forms

If $f\colon\mathbb{R}^n\longrightarrow\mathbb{R}$ is differentiable, then $Df(p)\in\Lambda^1(\mathbb{R}^n)$. By a minor modification we therefore obtain a $1$-form $\mathrm{d}f$, defined by $$\mathrm{d}f(p)(v_p)=Df(p)(v).$$ Let us consider in particular the $1$-forms $\mathrm{d}\pi^i$ ^[Spivak introduces the $\pi^i$ notation on page 11: "if $\pi\colon\mathbb{R}^n\longrightarrow\mathbb{R}^n$ is the identity function, $\pi(x)=x$, then [its components are] $\pi^i(x)=x^i$; the function $\pi^i$ is called the $i^\mathrm{th}$ *projection function*"]. It is customary to let $x^i$ denote the _function_ $\pi^i$ (on $\mathbb{R}^3$ we often denote $x^1$, $x^2$, and $x^3$ by $x$, $y$, and $z$) $\ldots$ Since $\mathrm{d}x^i(p)(v_p)=\mathrm{d}\pi^i(p)(v_p)=D\pi^i(p)(v)=v^i$, we see that $\mathrm{d}x^1(p),\ldots,\mathrm{d}x^n(p)$ is just the dual basis to $(e_1)_p,\ldots, (e_n)_p$.

- Michael Spivak, 1969 (Calculus on Manifolds, Perseus books). Page 89

Spivak goes on to observe that every $k$-form $\omega$ can be written $\omega=\sum_{i_1 < \cdots < i_k}\omega_{i_1,\ldots i_k}\mathrm{d}x^{i_1}\wedge\cdots\wedge\mathrm{d}x^{i_k}$. If working in $\mathbb{R}^3$, we have three elementary forms $\mathrm{d}x$, $\mathrm{d}y$, and $\mathrm{d}z$; in the package we have the pre-defined objects `dx`, `dy`, and `dz`. These are convenient for reproducing textbook results. We start with some illustrations of the package print method. ```{r label=showdx} dx ``` This is somewhat opaque and difficult to understand. It is easier to start with a more complicated example: take $\mathrm{d}x\wedge\mathrm{d}y -7\mathrm{d}x\wedge\mathrm{d}z + 3\mathrm{d}y\wedge\mathrm{d}z$: ```{r label=morecomplicatedcombination} dx^dy -7*dx^dz + 3*dy^dz ``` We see three rows for the three elementary components. Taking the row with coefficient $-7$ [which would be $-7\mathrm{d}x\wedge\mathrm{d}z$], this maps $\left(\mathbb{R}^3\right)^2$ to $\mathbb{R}$ and we have $$(-7\mathrm{d}x\wedge\mathrm{d}z)\left(\begin{pmatrix} u_1\\u_2\\u_3\end{pmatrix}, \begin{pmatrix}v_1\\v_2\\v_3\end{pmatrix}\right)= -7\det\begin{pmatrix}u_1&v_1\\u_3&v_3\end{pmatrix}$$ Armed with this familiar fact, we can interpret $dx$ as a map from $\left(\mathbb{R}^3\right)^1$ to $\mathbb{R}$ with $$\mathrm{d}x\left(\begin{pmatrix} u_1\\u_2\\u_3\end{pmatrix} \right)= \det\begin{pmatrix}u_1\end{pmatrix}=u_1$$ or, in other words, $\mathrm{d}x$ picks out the first component of its vector (as the print method gives, albeit obscurely). This is easily shown in the package: ```{r coercedxtoafunction} as.function(dx)(c(113,3,6)) ``` We might want to verify that $\mathrm{d}x\wedge\mathrm{d}y=-\mathrm{d}y\wedge\mathrm{d}x$: ```{r dxdyequalsminusdydx} dx ^ dy == -dy ^ dx ``` # Elementary forms and the print method The print method is configurable and can display kforms in symbolic form. For working with `dx dy dz` we may set option `kform_symbolic_print` to `dx`: ```{r setusedx} options(kform_symbolic_print = 'dx') ``` Then the results of calculations are more natural: ```{r showdxwithusedx} dx dx^dy + 56*dy^dz ``` However, this setting can be confusing if we work with $\mathrm{d}x^i,i>3$, for the print method runs out of alphabet: ```{r runsoutofalphabet} rform() ``` Above, we see the use of `NA` because there is no defined symbol. ## The Hodge dual Function `hodge()` returns the Hodge dual: ```{r hodgedxdydz} hodge(dx^dy + 13*dy^dz) ``` Note that calling `hodge(dx)` can be confusing: ```{r hodgedx} hodge(dx) ``` This returns a scalar because `dx` is interpreted as a one-form on one-dimensional space, which is a scalar form. One usually wants the result in three dimensions: ```{r hodgedx3} hodge(dx,3) ``` This is further discussed in the `dovs` vignette. ## Other ways to create the elementary one-forms It is possible to create these objects using package idiom: ```{r} d(1) == dx ``` ## Basis vectors ### Package dataset Following lines create `dx.rda`, residing in the `data/` directory of the package. ```{r,label=savedxdydz} save(dx,dy,dz,file="dx.rda") ``` # References